应对谷歌烧脑招聘面试题 你够聪明吗
Are YOU clever enough to answer Google's toughest interview questions?
Going for a job interview is nerve-racking at the best of times, but tech giant Google has become notorious for asking fiendishly tough questions.
即便是招聘高峰期,求职面试也会非常伤神费脑,然而科技巨头谷歌的面试题则因其奇葩刁钻而异常出名.
The company used to ask head-scratching questions such as 'How many piano tuners are there in the world?' and 'How many golf balls does it take to fill a school bus?'.
谷歌公司曾问过一些令人头痛不已的面试问题,例如,"世界上有多少位钢琴调音师？"以及"一辆校车里最多能塞多少颗高尔夫球？".
But some of the riddles were so tough they have now been banned from the interview process.
但因有些谜题太过于荒谬古怪,谷歌公司现在已不再将其纳入面试流程中.
Recruiter Impact Interview have compiled a list of 140 questions candidates have reported being asked at interviews for various roles at Google, many of which have now been dropped from the process.
招聘面试小册子汇编140道题,依应聘人员所言,在谷歌面试中他们曾以各种角色回答过此类问题.目前其中的许多问题已从面试流程中剔除.
One of the tough teasers that candidates used to be asked was: 'How many piano tuners are there in the entire world?'
应聘者们曾经回答过这样一个令人啼笑皆非的难题："全世界有多少位钢琴调音师？"
The riddle is known as a Fermi problem, named after the physicist Enrico Fermi who was known for his ability to make good calculations with very little information or even none.
这类谜题被称为"费米问题",命名来自物理学家恩里科·费米,他之所以声名远扬是因为他能够在少量的给定信息甚至没有信息的情况下进行运算.
Its purpose is to test a candidates approximation skills as well as their ability at dimensional analysis.
费米问题意在考察应聘者的估算能力以及量纲分析能力.
The puzzle is solved by multiplying a series of estimates to get to the right answer. So a candidate would have to estimate factors such as how many households have a piano, how often they are tuned to figure out how many piano tunings take place a year.
解决费米问题的方法在于通过一系列估算而无限接近正确答案.因此,应聘者需要考量一些因素,诸如：拥有钢琴的家庭户数,此类家庭进行钢琴调音的频次等,从而得出每年有多少次的钢琴调音.
They then need to calculate the average working hours of a piano tuners and the number of jobs they carry out.
随后,应聘者们需要估算出钢琴调音师的平均工作时长以及工作量.
The number of piano tunings that take place per year divided by the number per year per piano tuner should yield the answer.
因此,用每年所有家庭需要进行钢琴调音的次数除以每年每位钢琴调音师的工作量,答案就此诞生.
